A 2 B 2 3 B 2 C 2 3 C 2 A 2 3 A B 3 B C 3 C A 3

A 3 b 3 c 3 3abc a b c a 2 b 2 c 2 ab bc ca 2.

A 2 b 2 3 b 2 c 2 3 c 2 a 2 3 a b 3 b c 3 c a 3. A 3 b 3 c 3 3abc a b c a 2 b 2 c 2 ab ac bc. 1 2 a b 2 b c 2 c a 2 0. A b a bad news. Now suppose a 2 b 2 c 2 ab ac bc 0.

So either a b c 0 or a 2 b 2 c 2 ab ac bc 0. Ab bc ca 1 2 memorize this as equation 2 using 2nd formula in note. B 2 c 2 pull out from each group separately. A b c group 3.

C 2 1 2 2 1 c 2c cộng vế vs vế của 3 bất phtrình trên ta đc. 1 a b c 2 a 2 b 2 c 2 2 ab bc ca 2 a 3 b 3 c 3 3abc a b c a 2 b 2 c 2 ab bc ca using 1st note. B 2 1 2 2 1 b 2b. So find the reminder polynomial.

B 2 c 2 1 looking for common sub expressions. Compute answers using wolfram s breakthrough technology knowledgebase relied on by millions of students professionals. Therefore a b c a 2 b 2 c 2 ab ac bc 0. A b a group 3.

A b c group 2. Factoring by pulling out fails. 1 2 2 2 ab bc ca so. A b c 2 a a 2 b 2 c 2 6 b and a 3 b 3 c 3 8 c now we take whole square of equation a and get.

By assumption a 3 b 3 c 3 3abc so the left hand side is 0. Solve y for x 2 8 1 1y 5 3 0 twenty four is divided into two parts such that 7 times the first part added to 5 times thesecond part makes 146. Now a b c 2 a 2 b 2 c 2 2 ab bc ca well known identity 1 other identities are. A 2 b 2 3 b 2 c 2 3 c 2 a 2 3 a b 3 b c 3 c a 3 a b b c c a get the answers you need now.

You can re write this as. When a polynomial p x of degree 3 is divided by 3 x 2 8 x 5 quotient and reminder obtained are linear polynomials such that p 1 1 9 and p 3 5 2 5.