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A b 3 b c 3 c a 3.
A b 3 b c 3 c a 3 formula. Now i am going to explain everything below. You can also check cube formula in algebra formula sheet. This is just multiplying out and bookkeeping. You will have 27 a b c 3 a b c then divide both sides by 3.
A2 b2 a b a b a b 2 a2 2ab b2 a2 b2 a. But anyway to prove this without knowing anything. If a b and c are all real positive numbers then it will be correct. A 3 b 3 c 3 3abc a b c a 2 b 2 c 2 ab bc ac if a b c 0 a 3 b 3 c 3 3abc some not so common formulas.
You will have 9 a b c a b c. Factor out the 3 in the portion on the right. A b c b c a c a b expand the cubes and cancel the equal and opposite terms. This is the solution of question from rd sharma book of class 9 chapter polynomials this question is also available in r s aggarwal book of class 9 you can find.
Share with your friends. A b a c 3 a b c b c b c b a 3 b a c c a. You can check and revert back if you like. And using the identity.
Hope this helps you. A 3 b 3 c 3 plus 3 of each term having one variable and another one squared like ab 2 b 2c all 6 combinations of those then plus 6abc and that s it. Note that we can expand the a b 3 b c 3 and c a 3 using the special product formulas for a cube of a binomial.
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